What is (5+7)^2-y^2=-7x+4 ?

The solution to (5+7)^2-y^2=-7x+4 is Parabola with (h,k)=(-20,0),p= 7/4

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(5+7)^2-y^2=-7x+4

(5 + 7)^{2} - y^{2} = - 7 x + 4

(h, k) = (- 20, 0), p = \frac{7}{4}

Solution steps

(5 + 7)^{2} - y^{2} = - 7 x + 4

Rewrite

(5 + 7)^{2} - y^{2} = - 7 x + 4

in the standard form:

4 \cdot \frac{7}{4} (x - (- 20)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 20, 0), p = \frac{7}{4}

x = (y - 7)^{2}

\frac{y - x ^{2}}{y ^{2} - x} = 0

(3 - x)^{2} + y = 0

d = (x 1 - x 2)^{2} + (y 1 + y 2)^{2}

3 y^{2} + 18 y - x + 22 = 0

What is (5+7)^2-y^2=-7x+4 ?
The solution to (5+7)^2-y^2=-7x+4 is Parabola with (h,k)=(-20,0),p= 7/4