What is 1/2 f(x)=(x^2+7)+1 ?

The solution to 1/2 f(x)=(x^2+7)+1 is Parabola with (h,k)=(0,2),p= 1/8

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1/2 f(x)=(x^2+7)+1

\frac{1}{2} f (x) = (x^{2} + 7) + 1

(h, k) = (0, 2), p = \frac{1}{8}

Solution steps

\frac{1}{2} y = (x^{2} + 7) + 1

Rewrite

\frac{1}{2} y = (x^{2} + 7) + 1

in the standard form:

4 \cdot \frac{1}{8} (y - 2) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = \frac{1}{8}

x, 10 w (x)^{2} = 7 x + 6

3 x - 2 y = x^{2} + 1

2 f (x) = 2 x^{2} + 3 x - 4

(x + 2)^{2} = 8 y - 24

2 x = y^{2} + 8 y + 22

What is 1/2 f(x)=(x^2+7)+1 ?
The solution to 1/2 f(x)=(x^2+7)+1 is Parabola with (h,k)=(0,2),p= 1/8