What is (x+2)^2=4(y-3) ?

The solution to (x+2)^2=4(y-3) is Parabola with (h,k)=(-2,3),p=1

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(x+2)^2=4(y-3)

(x + 2)^{2} = 4 (y - 3)

(h, k) = (- 2, 3), p = 1

Solution steps

(x + 2)^{2} = 4 (y - 3)

Rewrite

(x + 2)^{2} = 4 (y - 3)

in the standard form:

4 \cdot 1 \cdot (y - 3) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 3), p = 1

x, x = 5 - 12.5 (t (x) + 2) + \frac{10.4 ( t ( x ) + 2 ) ^{2}}{2}

x^{2} - 10 x - 63 y = - 25 - 63

y^{2} - 28 x - 16 y + 8 = 0

x + y^{2} - 3 > 0

- x + y^{2} - 2 y + 2 = 0

What is (x+2)^2=4(y-3) ?
The solution to (x+2)^2=4(y-3) is Parabola with (h,k)=(-2,3),p=1