What is 2f(x)=5(x)^2-(x)+4 ?

The solution to 2f(x)=5(x)^2-(x)+4 is Parabola with (h,k)=(1/10 , 79/40),p= 1/10

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2f(x)=5(x)^2-(x)+4

2 f (x) = 5 (x)^{2} - (x) + 4

(h, k) = (\frac{1}{10}, \frac{79}{40}), p = \frac{1}{10}

Solution steps

2 y = 5 x^{2} - x + 4

Rewrite

2 y = 5 x^{2} - x + 4

in the standard form

4 \cdot \frac{1}{10} (y - \frac{79}{40}) = (x - \frac{1}{10})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{10}, \frac{79}{40}), p = \frac{1}{10}

x + 2 (y - 1)^{2} = 0

x^{2} = - \frac{125}{4} (y - 20)

(y - 4)^{2} = 4 - 4 x

9 L (x) = \frac{x}{3 L ( x )}

y = \frac{1}{4} (x^{2} - 2 x + 5)

What is 2f(x)=5(x)^2-(x)+4 ?
The solution to 2f(x)=5(x)^2-(x)+4 is Parabola with (h,k)=(1/10 , 79/40),p= 1/10