What is x^2+3x+k(x)-4=0 ?

The solution to x^2+3x+k(x)-4=0 is Parabola with (h,k)=(-3/2 , 25/4),p=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+3x+k(x)-4=0

x^{2} + 3 x + k (x) - 4 = 0

(h, k) = (- \frac{3}{2}, \frac{25}{4}), p = - \frac{1}{4}

Solution steps

x^{2} + 3 x + y - 4 = 0

Rewrite

x^{2} + 3 x + y - 4 = 0

in the standard form

4 (- \frac{1}{4}) (y - \frac{25}{4}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{25}{4}), p = - \frac{1}{4}

x^{2} + 8 x - 36 y + 340 = 0

12 a^{2} + 5 b = 8 b

x^{2} + 1 = 2 x + k (x)

c x^{2} + x^{2} + y = 0

f (x) = 2 x^{2} + 2 x - 2 s i f (- 2)

What is x^2+3x+k(x)-4=0 ?
The solution to x^2+3x+k(x)-4=0 is Parabola with (h,k)=(-3/2 , 25/4),p=-1/4