What is 4-(y-4)2=(x^2+6x+9) ?

The solution to 4-(y-4)2=(x^2+6x+9) is Parabola with (h,k)=(-3,2),p=-1/2

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4-(y-4)2=(x^2+6x+9)

4 - (y - 4) 2 = (x^{2} + 6 x + 9)

(h, k) = (- 3, 2), p = - \frac{1}{2}

Solution steps

4 - (y - 4) \cdot 2 = (x^{2} + 6 x + 9)

Rewrite

4 - (y - 4) \cdot 2 = (x^{2} + 6 x + 9)

in the standard form

4 (- \frac{1}{2}) (y - 2) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 2), p = - \frac{1}{2}

x = \frac{3}{2} y^{2} - 3

2 y + 3 x^{2} = 10

3 x + 2 y^{2} = 7

(y - (- 6))^{2} = 2 (x - 1)

y^{2} + 8 = 33 - x

What is 4-(y-4)2=(x^2+6x+9) ?
The solution to 4-(y-4)2=(x^2+6x+9) is Parabola with (h,k)=(-3,2),p=-1/2