What is y-20=-4(1/1280)(x-80)^2 ?

The solution to y-20=-4(1/1280)(x-80)^2 is Parabola with (h,k)=(80,20),p=-80

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y-20=-4(1/1280)(x-80)^2

y - 20 = - 4 (\frac{1}{1280}) (x - 80)^{2}

(h, k) = (80, 20), p = - 80

Solution steps

y - 20 = - 4 \cdot \frac{1}{1280} (x - 80)^{2}

Rewrite

y - 20 = - 4 \cdot \frac{1}{1280} (x - 80)^{2}

in the standard form:

4 (- 80) (y - 20) = (x - 80)^{2}

Therefore parabola properties are:

(h, k) = (80, 20), p = - 80

(y + 4)^{2} = x + 3

(y - 4)^{2} = - 8 (x + 3)

(x - 2)^{2} = 5 (y - 1)

y = 40 x - 2 x^{2}

x^{2} - 2 y = 3 x + 22

What is y-20=-4(1/1280)(x-80)^2 ?
The solution to y-20=-4(1/1280)(x-80)^2 is Parabola with (h,k)=(80,20),p=-80