What is 7x^2+3x+k(x)=0 ?

The solution to 7x^2+3x+k(x)=0 is Parabola with (h,k)=(-3/14 , 9/28),p=-1/28

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7x^2+3x+k(x)=0

7 x^{2} + 3 x + k (x) = 0

(h, k) = (- \frac{3}{14}, \frac{9}{28}), p = - \frac{1}{28}

Solution steps

7 x^{2} + 3 x + y = 0

Rewrite

7 x^{2} + 3 x + y = 0

in the standard form

4 (- \frac{1}{28}) (y - \frac{9}{28}) = (x - (- \frac{3}{14}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{14}, \frac{9}{28}), p = - \frac{1}{28}

x^{2} - 36 x + 16 y + 68 = 0

4 x^{2} + 5 y - 3 = 0

(x - 2)^{2} + y = 1

x^{2} - 3 x - m (x) = 0

\frac{1 - p ( x )}{3} - \frac{7 x}{6} + x^{2} = 0

What is 7x^2+3x+k(x)=0 ?
The solution to 7x^2+3x+k(x)=0 is Parabola with (h,k)=(-3/14 , 9/28),p=-1/28