What is Δf(x)=5.15*y^2-0.15 ?

The solution to Δf(x)=5.15*y^2-0.15 is Parabola with (h,k)=(-(0.15)/(Δf),0),p=0.04854…Δf

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Δf(x)=5.15*y^2-0.15

Δ f (x) = 5.15 \cdot y^{2} - 0.15

(h, k) = (- \frac{0.15}{Δ f}, 0), p = 0.04854 \dots Δ f

Solution steps

Δ f x = 5.15 y^{2} - 0.15

Rewrite

Δ f x = 5.15 y^{2} - 0.15

in the standard form:

4 \cdot 0.04854 \dots Δ f (x - (- \frac{0.15}{Δ f})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{0.15}{Δ f}, 0), p = 0.04854 \dots Δ f

4 x^{2} - 12 y + 7 = 0

\frac{9 \cdot 1 0 ^{9} \cdot x ^{2}}{y} = 100

(y)^{2} = 4 a (x - h)

(x + 7)^{2} + (y - 3) = 100

y > - x^{2}

What is Δf(x)=5.15*y^2-0.15 ?
The solution to Δf(x)=5.15*y^2-0.15 is Parabola with (h,k)=(-(0.15)/(Δf),0),p=0.04854…Δf