What is 4x^2-12x^2+8x-2y=-2 ?

The solution to 4x^2-12x^2+8x-2y=-2 is Parabola with (h,k)=(1/2 ,2),p=-1/16

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4x^2-12x^2+8x-2y=-2

4 x^{2} - 12 x^{2} + 8 x - 2 y = - 2

(h, k) = (\frac{1}{2}, 2), p = - \frac{1}{16}

Solution steps

4 x^{2} - 12 x^{2} + 8 x - 2 y = - 2

Rewrite

4 x^{2} - 12 x^{2} + 8 x - 2 y = - 2

in the standard form

4 (- \frac{1}{16}) (y - 2) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, 2), p = - \frac{1}{16}

x d x + e

x (1 - x) + m (x) = 0

(x + 1) + y^{2} = 4

x^{2} - 6 x + 4 + p (x) = 0

y = - 2 x^{2} + 7

What is 4x^2-12x^2+8x-2y=-2 ?
The solution to 4x^2-12x^2+8x-2y=-2 is Parabola with (h,k)=(1/2 ,2),p=-1/16