What is 21x-32y^2=4-7y ?

The solution to 21x-32y^2=4-7y is Parabola with (h,k)=(463/2688 , 7/64),p= 21/128

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21x-32y^2=4-7y

21 x - 32 y^{2} = 4 - 7 y

(h, k) = (\frac{463}{2688}, \frac{7}{64}), p = \frac{21}{128}

Solution steps

21 x - 32 y^{2} = 4 - 7 y

Rewrite

21 x - 32 y^{2} = 4 - 7 y

in the standard form

4 \cdot \frac{21}{128} (x - \frac{463}{2688}) = (y - \frac{7}{64})^{2}

Therefore parabola properties are:

(h, k) = (\frac{463}{2688}, \frac{7}{64}), p = \frac{21}{128}

x^{2} - 14 x + 4 y + 45 = 0

(x + 4)^{2} = 12 (y - 1)

2 x^{2} + 3 y = 7

- 4 x + x^{2} + 2 y + 4 = 0

2 x - 4 y^{2} = 3

What is 21x-32y^2=4-7y ?
The solution to 21x-32y^2=4-7y is Parabola with (h,k)=(463/2688 , 7/64),p= 21/128