What is x^2-3x+(1-3p(x))/6 =0 ?

The solution to x^2-3x+(1-3p(x))/6 =0 is Parabola with (h,k)=(3/2 ,-9/2),p= 1/8

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x^2-3x+(1-3p(x))/6 =0

x^{2} - 3 x + \frac{1 - 3 p ( x )}{6} = 0

(h, k) = (\frac{3}{2}, - \frac{9}{2}), p = \frac{1}{8}

Solution steps

x^{2} - 3 x + \frac{1 - 3 y}{6} = 0

Rewrite

x^{2} - 3 x + \frac{1 - 3 y}{6} = 0

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{9}{2})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{9}{2}), p = \frac{1}{8}

3 x^{2} + 2 x + 5 y - 6 = 0

y^{2} - 12 x + 16 y + 68 = 0

y^{2} - 24 x = 0

((x) - (3))^{2} = (4) (3) (y - (0))

x + y^{2} - 7 > 0

What is x^2-3x+(1-3p(x))/6 =0 ?
The solution to x^2-3x+(1-3p(x))/6 =0 is Parabola with (h,k)=(3/2 ,-9/2),p= 1/8