What is x-5=(y-3)^2 ?

The solution to x-5=(y-3)^2 is Parabola with (h,k)=(5,3),p= 1/4

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x-5=(y-3)^2

x - 5 = (y - 3)^{2}

(h, k) = (5, 3), p = \frac{1}{4}

Solution steps

x - 5 = (y - 3)^{2}

Rewrite

x - 5 = (y - 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 5) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (5, 3), p = \frac{1}{4}

\frac{x}{4} x + 12 y = 12

4 x + 1 = - 6 w (x, y) y

q, q 4 q = 5 t + 2 q^{2}

- 3 x^{2} + 18 x - y + 37 = 0

x, 3 x^{2} + 27 w = 0

What is x-5=(y-3)^2 ?
The solution to x-5=(y-3)^2 is Parabola with (h,k)=(5,3),p= 1/4