What is (x-6)^2+(y-(-4)^2=5) ?

The solution to (x-6)^2+(y-(-4)^2=5) is Parabola with (h,k)=(6,21),p=-1/4

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(x-6)^2+(y-(-4)^2=5)

(x - 6)^{2} + (y - (- 4)^{2} = 5)

(h, k) = (6, 21), p = - \frac{1}{4}

Solution steps

(x - 6)^{2} + y - (- 4)^{2} = 5

Rewrite

(x - 6)^{2} + y - (- 4)^{2} = 5

in the standard form:

4 (- \frac{1}{4}) (y - 21) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, 21), p = - \frac{1}{4}

v (137.5) = (- 1.04149 t + 275)^{2}

yy + x = 55

x = - 10 y^{2} + 5

yy - 320 = 40 (x - 2010)

y^{2} + 4 y + 6 x - 5 = 0

What is (x-6)^2+(y-(-4)^2=5) ?
The solution to (x-6)^2+(y-(-4)^2=5) is Parabola with (h,k)=(6,21),p=-1/4