What is -x^2+6x-16y+41=0 ?

The solution to -x^2+6x-16y+41=0 is Parabola with (h,k)=(3, 25/8),p=-4

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-x^2+6x-16y+41=0

- x^{2} + 6 x - 16 y + 41 = 0

(h, k) = (3, \frac{25}{8}), p = - 4

Solution steps

- x^{2} + 6 x - 16 y + 41 = 0

Rewrite

- x^{2} + 6 x - 16 y + 41 = 0

in the standard form

4 (- 4) (y - \frac{25}{8}) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, \frac{25}{8}), p = - 4

(x - 3)^{2} = - 3 (y + 4)

x = y^{2} + 6 y

(y - 1)^{2} = 12 (x - 6)

x = y^{2} + 13

x = y^{2} + 15

What is -x^2+6x-16y+41=0 ?
The solution to -x^2+6x-16y+41=0 is Parabola with (h,k)=(3, 25/8),p=-4