What is y^2-10x-4y-14=0 ?

The solution to y^2-10x-4y-14=0 is Parabola with (h,k)=(-9/5 ,2),p= 5/2

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y^2-10x-4y-14=0

y^{2} - 10 x - 4 y - 14 = 0

(h, k) = (- \frac{9}{5}, 2), p = \frac{5}{2}

Solution steps

y^{2} - 10 x - 4 y - 14 = 0

Rewrite

y^{2} - 10 x - 4 y - 14 = 0

in the standard form

4 \cdot \frac{5}{2} (x - (- \frac{9}{5})) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{5}, 2), p = \frac{5}{2}

4 x^{2} - 7 y = 9

r^{2} - s = 0

y \frac{y}{204} + \frac{x}{1.265} = 3026

x + y = x^{2}

y^{2} - 6 y - 12 x - 39 = 0

What is y^2-10x-4y-14=0 ?
The solution to y^2-10x-4y-14=0 is Parabola with (h,k)=(-9/5 ,2),p= 5/2