What is (y-(-2))^2=2(1)(x-(-1)) ?

The solution to (y-(-2))^2=2(1)(x-(-1)) is Parabola with (h,k)=(-1,-2),p= 1/2

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(y-(-2))^2=2(1)(x-(-1))

(y - (- 2))^{2} = 2 (1) (x - (- 1))

(h, k) = (- 1, - 2), p = \frac{1}{2}

Solution steps

(y - (- 2))^{2} = 2 \cdot 1 \cdot (x - (- 1))

Rewrite

(y - (- 2))^{2} = 2 \cdot 1 \cdot (x - (- 1))

in the standard form:

4 \cdot \frac{1}{2} (x - (- 1)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 2), p = \frac{1}{2}

y < 3 x^{2} - 6 x + 5

(x - 3)^{2} = 20 (y + \frac{119}{20})

(x - 1)^{2} = 2 y

y - (4 x)^{2} = 0

5 x^{2} + 3 y = 41

What is (y-(-2))^2=2(1)(x-(-1)) ?
The solution to (y-(-2))^2=2(1)(x-(-1)) is Parabola with (h,k)=(-1,-2),p= 1/2