What is x^2+2y^2-8y=0 ?

The solution to x^2+2y^2-8y=0 is Ellipse with (h,k)=(0,2),a=2sqrt(2),b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+2y^2-8y=0

x^{2} + 2 y^{2} - 8 y = 0

(h, k) = (0, 2), a = 22, b = 2

Solution steps

x^{2} + 2 y^{2} - 8 y = 0

Rewrite

x^{2} + 2 y^{2} - 8 y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 2), a = 22, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 2), a = 22, b = 2

x^{2} - y^{2} = 4

y^{2} + 6 y - 2 x + 13 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

f (x) = x^{2} + 2 x - 8

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

What is x^2+2y^2-8y=0 ?
The solution to x^2+2y^2-8y=0 is Ellipse with (h,k)=(0,2),a=2sqrt(2),b=2