What is f(x)(x)^{-1}=(x-4)/(11) ?

The solution to f(x)(x)^{-1}=(x-4)/(11) is Parabola with (h,k)=(2,-4/11),p= 11/4

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f(x)(x)^{-1}=(x-4)/(11)

f (x) (x)^{- 1} = \frac{x - 4}{11}

(h, k) = (2, - \frac{4}{11}), p = \frac{11}{4}

Solution steps

y x^{- 1} = \frac{x - 4}{11}

Rewrite

y x^{- 1} - \frac{x - 4}{11} = 0

in the standard form

4 \cdot \frac{11}{4} (y - (- \frac{4}{11})) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - \frac{4}{11}), p = \frac{11}{4}

4 x - x^{2} + 2 y = 0

x^{2} + 5 y = 20

x^{2} = x + y

(x + \frac{3}{2})^{2} = 4 (y - 2)

x^{2} + 5 y = 10

What is f(x)(x)^{-1}=(x-4)/(11) ?
The solution to f(x)(x)^{-1}=(x-4)/(11) is Parabola with (h,k)=(2,-4/11),p= 11/4