What is 2y^2+9y-x=0 ?

The solution to 2y^2+9y-x=0 is Parabola with (h,k)=(-81/8 ,-9/4),p= 1/8

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2y^2+9y-x=0

2 y^{2} + 9 y - x = 0

(h, k) = (- \frac{81}{8}, - \frac{9}{4}), p = \frac{1}{8}

Solution steps

2 y^{2} + 9 y - x = 0

Rewrite

2 y^{2} + 9 y - x = 0

in the standard form

4 \cdot \frac{1}{8} (x - (- \frac{81}{8})) = (y - (- \frac{9}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{81}{8}, - \frac{9}{4}), p = \frac{1}{8}

x, x = - 4 (t (x) - 1)^{2} + 100

y + 3 = \frac{1}{4} (x - 2)^{2}

- f (x) + 4 = 2 x^{2} - 4 x + 1

x^{2} - 4 x - 12 y - 56 = 0

y^{2} + 2 x - 2 y - 3 = 0

What is 2y^2+9y-x=0 ?
The solution to 2y^2+9y-x=0 is Parabola with (h,k)=(-81/8 ,-9/4),p= 1/8