What is the axis y=x^2 ?

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axis y=x^2

axis

y = x^{2}

x = 0

Solution steps

y = x^{2}

Rewrite

y = x^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

f (x) = x^{2} - 4 x - 12

25 y^{2} - 36 (x - 8)^{2} = 900

x^{2} + y^{2} - 4 = 0

x = - \frac{1}{2} (y + 3)^{2} + 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1