What is 4(-1/8)(x-57/8)=(y-5/4)^2 ?

The solution to 4(-1/8)(x-57/8)=(y-5/4)^2 is Parabola with (h,k)=(57/8 , 5/4),p=-1/8

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4(-1/8)(x-57/8)=(y-5/4)^2

4 (- \frac{1}{8}) (x - \frac{57}{8}) = (y - \frac{5}{4})^{2}

(h, k) = (\frac{57}{8}, \frac{5}{4}), p = - \frac{1}{8}

Solution steps

4 (- \frac{1}{8}) (x - \frac{57}{8}) = (y - \frac{5}{4})^{2}

Rewrite

4 (- \frac{1}{8}) (x - \frac{57}{8}) = (y - \frac{5}{4})^{2}

in the standard form:

4 (- \frac{1}{8}) (x - \frac{57}{8}) = (y - \frac{5}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{57}{8}, \frac{5}{4}), p = - \frac{1}{8}

2 x^{2} - 20 x + 2 m (x) > 0

x^{2} + 2 x - y = 2

4 x^{2} + 4 y = 25

4 x^{2} > y - 3

4 g (x) = 5 x^{2} + 9 x + 4

What is 4(-1/8)(x-57/8)=(y-5/4)^2 ?
The solution to 4(-1/8)(x-57/8)=(y-5/4)^2 is Parabola with (h,k)=(57/8 , 5/4),p=-1/8