What is 4x^2+6x^2+4x-2y=0 ?

The solution to 4x^2+6x^2+4x-2y=0 is Parabola with (h,k)=(-1/5 ,-1/5),p= 1/20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+6x^2+4x-2y=0

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

(h, k) = (- \frac{1}{5}, - \frac{1}{5}), p = \frac{1}{20}

Solution steps

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

Rewrite

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

in the standard form

4 \cdot \frac{1}{20} (y - (- \frac{1}{5})) = (x - (- \frac{1}{5}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{5}, - \frac{1}{5}), p = \frac{1}{20}

17 x^{2} + 16 y = 272

6 x^{2} + 7 x + k (x) = 0

- y = 1 - x^{2}

y + 61 = 2 x (x - 61)

(x - 14)^{2} = 4 (y - 18)

What is 4x^2+6x^2+4x-2y=0 ?
The solution to 4x^2+6x^2+4x-2y=0 is Parabola with (h,k)=(-1/5 ,-1/5),p= 1/20