What is -y+6+2x^2=x^2+25 ?

The solution to -y+6+2x^2=x^2+25 is Parabola with (h,k)=(0,-19),p= 1/4

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-y+6+2x^2=x^2+25

- y + 6 + 2 x^{2} = x^{2} + 25

(h, k) = (0, - 19), p = \frac{1}{4}

Solution steps

- y + 6 + 2 x^{2} = x^{2} + 25

Rewrite

- y + 6 + 2 x^{2} = x^{2} + 25

in the standard form:

4 \cdot \frac{1}{4} (y - (- 19)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 19), p = \frac{1}{4}

(x - 2)^{2} = - 16 (y - 2)

(x - 1)^{2} = 16 (y - 3)

(y - 3)^{2} = - \frac{3 ( x - 3 )}{2}

9 x^{2} - 36 x + 4 y = 0

(y + 2)^{2} = 4 (x - 3)

What is -y+6+2x^2=x^2+25 ?
The solution to -y+6+2x^2=x^2+25 is Parabola with (h,k)=(0,-19),p= 1/4