What is a(v_{2})/4 =v^2-2ad ?

The solution to a(v_{2})/4 =v^2-2ad is Parabola with (h,k)=(-8d,0),p= a/(16)

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a(v_{2})/4 =v^2-2ad

a \frac{v _{2}}{4} = v^{2} - 2 a d

(h, k) = (- 8 d, 0), p = \frac{a}{16}

Solution steps

a \frac{v _{2}}{4} = v^{2} - 2 a d

Rewrite

a \frac{v _{2}}{4} = v^{2} - 2 a d

in the standard form:

4 \cdot \frac{a}{16} (v_{2} - (- 8 d)) = (v - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 8 d, 0), p = \frac{a}{16}

\frac{y}{18 + x} + \frac{1}{15} = \frac{y}{x}

x^{2} - 4 x + m (x) = 0

3 x^{2} - 6 x - 6 y + 10 = 0

A y^{2} - 6 x = 0

2 x + 2 y^{2} = 0

What is a(v_{2})/4 =v^2-2ad ?
The solution to a(v_{2})/4 =v^2-2ad is Parabola with (h,k)=(-8d,0),p= a/(16)