What is -f(x)=4(x)^2+4(x)-2 ?

The solution to -f(x)=4(x)^2+4(x)-2 is Parabola with (h,k)=(-1/2 ,3),p=-1/16

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-f(x)=4(x)^2+4(x)-2

- f (x) = 4 (x)^{2} + 4 (x) - 2

(h, k) = (- \frac{1}{2}, 3), p = - \frac{1}{16}

Solution steps

- y = 4 x^{2} + 4 x - 2

Rewrite

- y = 4 x^{2} + 4 x - 2

in the standard form

4 (- \frac{1}{16}) (y - 3) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, 3), p = - \frac{1}{16}

x, - 2 x + 4 k (x)^{2} = - 15

(x + 3)^{2} - 49 = - y

(y + 2)^{2} = - 4 (x - 3)

x^{2} - 8 x + 4 y + 24 = 0

2 v = 3 u^{2}

What is -f(x)=4(x)^2+4(x)-2 ?
The solution to -f(x)=4(x)^2+4(x)-2 is Parabola with (h,k)=(-1/2 ,3),p=-1/16