What is f(x)(a-9)=2x^2+8 ?

The solution to f(x)(a-9)=2x^2+8 is Parabola with (h,k)=(0, 8/(a-9)),p=(a-9)/8

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f(x)(a-9)=2x^2+8

f (x) (a - 9) = 2 x^{2} + 8

(h, k) = (0, \frac{8}{a - 9}), p = \frac{a - 9}{8}

Solution steps

y (a - 9) = 2 x^{2} + 8

Rewrite

y (a - 9) = 2 x^{2} + 8

in the standard form:

4 \cdot \frac{a - 9}{8} (y - \frac{8}{a - 9}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{8}{a - 9}), p = \frac{a - 9}{8}

x = \frac{y ^{2}}{4} + 1

4 x^{2} - 8 x + 3 y - 2 = 0

(x - \frac{7}{4}) + (y + \frac{3}{4})^{2} = \frac{169}{16}

y^{2} - 10 x + y = 0

\frac{a - 1}{b} = \frac{a + 1}{b} + \frac{b - 1}{a}

What is f(x)(a-9)=2x^2+8 ?
The solution to f(x)(a-9)=2x^2+8 is Parabola with (h,k)=(0, 8/(a-9)),p=(a-9)/8