What is (x^2}{25}-\frac{y^2)/9 =1 ?

The solution to (x^2}{25}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=5,b=3

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(x^2}{25}-\frac{y^2)/9 =1

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 5, b = 3

Solution steps

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 3

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

y^{2} - x^{2} = 1

x^{2} + 4 y^{2} - 6 x + 20 y - 2 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

What is (x^2}{25}-\frac{y^2)/9 =1 ?
The solution to (x^2}{25}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=5,b=3