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Popular >

foci 5x^2+7y^2=35

Solution

foci

5 x^{2} + 7 y^{2} = 35

Solution

(2, 0), (- 2, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

5 x^{2} + 7 y^{2} = 35 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} - 5^{2} : 2

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

Popular Examples

((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

\frac{( x + 3 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{9} = 1

16x^2-96x+144+25y^2=400

16 x^{2} - 96 x + 144 + 25 y^{2} = 400

directrix x^2=20y directrix

x^{2} = 20 y

vertices x^2=4y vertices

x^{2} = 4 y

x^{2} + y^{2} = 8

Frequently Asked Questions (FAQ)

What is the foci 5x^2+7y^2=35 ?
The foci 5x^2+7y^2=35 is (sqrt(2),0),(-sqrt(2),0)