What is (x+1)^2=-3/2 (y-4/3 x-2/3) ?

The solution to (x+1)^2=-3/2 (y-4/3 x-2/3) is Parabola with (h,k)=(0,0),p=-3/8

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(x+1)^2=-3/2 (y-4/3 x-2/3)

(x + 1)^{2} = - \frac{3}{2} (y - \frac{4}{3} x - \frac{2}{3})

(h, k) = (0, 0), p = - \frac{3}{8}

Solution steps

(x + 1)^{2} = - \frac{3}{2} (y - \frac{4}{3} x - \frac{2}{3})

Rewrite

(x + 1)^{2} + \frac{3}{2} (y - \frac{4}{3} x - \frac{2}{3}) = 0

in the standard form

4 (- \frac{3}{8}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{3}{8}

x^{2} + 2 x + 1 = 16 y

- x^{2} + 121 s = 0

y^{2} + 4 y - x + 4 = 0

x^{2} + 6 x - 4 y - 3 = 0

x^{2} - 3 y = 0

What is (x+1)^2=-3/2 (y-4/3 x-2/3) ?
The solution to (x+1)^2=-3/2 (y-4/3 x-2/3) is Parabola with (h,k)=(0,0),p=-3/8