What is 3x^2+5x+k(x)=0 ?

The solution to 3x^2+5x+k(x)=0 is Parabola with (h,k)=(-5/6 , 25/12),p=-1/12

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3x^2+5x+k(x)=0

3 x^{2} + 5 x + k (x) = 0

(h, k) = (- \frac{5}{6}, \frac{25}{12}), p = - \frac{1}{12}

Solution steps

3 x^{2} + 5 x + y = 0

Rewrite

3 x^{2} + 5 x + y = 0

in the standard form

4 (- \frac{1}{12}) (y - \frac{25}{12}) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, \frac{25}{12}), p = - \frac{1}{12}

(x + 1)^{2} = 12 (y - 0)

y = - x^{2} + 18 x

\frac{x}{5} x + 15 y = 15

2 x^{2} + 5 x - 2 = o

(y - 2)^{2} = - 8 (x - 5)

What is 3x^2+5x+k(x)=0 ?
The solution to 3x^2+5x+k(x)=0 is Parabola with (h,k)=(-5/6 , 25/12),p=-1/12