What is y^2-1/5 x+2y=-19/5 ?

The solution to y^2-1/5 x+2y=-19/5 is Parabola with (h,k)=(14,-1),p= 1/20

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y^2-1/5 x+2y=-19/5

y^{2} - \frac{1}{5} x + 2 y = - \frac{19}{5}

(h, k) = (14, - 1), p = \frac{1}{20}

Solution steps

y^{2} - \frac{1}{5} x + 2 y = - \frac{19}{5}

Rewrite

y^{2} - \frac{1}{5} x + 2 y = - \frac{19}{5}

in the standard form

4 \cdot \frac{1}{20} (x - 14) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (14, - 1), p = \frac{1}{20}

x = (h (x) + 1)^{2}

x + 5 y^{2} + y - 4 ey = 2 x

(y + 2)^{2} = 32 (x - 3)

y - 5 = 0.5 x^{2} + 6 x - 3

y^{2} + 4 x - 20 - 2 y = - x

What is y^2-1/5 x+2y=-19/5 ?
The solution to y^2-1/5 x+2y=-19/5 is Parabola with (h,k)=(14,-1),p= 1/20