What is y0.05y+0.01x<= 1.2 ?

The solution to y0.05y+0.01x<= 1.2 is Parabola with (h,k)=(120,0),p=-1/20

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y0.05y+0.01x<= 1.2

y 0.05 y + 0.01 x \leq 1.2

(h, k) = (120, 0), p = - \frac{1}{20}

Solution steps

y \cdot 0.05 y + 0.01 x \leq 1.2

Rewrite

y \cdot 0.05 y + 0.01 x \leq 1.2

in the standard form:

4 (- \frac{1}{20}) (x - 120) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (120, 0), p = - \frac{1}{20}

x^{2} = - 100 (y)

(x - 5)^{2} = 8 (y + 3)

3 x^{2} - 6 x + m (x) = 0

(y - 1)^{2} = 16 (x - 4)

y^{2} - 4 y + 4 x - 4 = 0

What is y0.05y+0.01x<= 1.2 ?
The solution to y0.05y+0.01x<= 1.2 is Parabola with (h,k)=(120,0),p=-1/20