What is 2y^2-x-3y-4=0 ?

The solution to 2y^2-x-3y-4=0 is Parabola with (h,k)=(-41/8 , 3/4),p= 1/8

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2y^2-x-3y-4=0

2 y^{2} - x - 3 y - 4 = 0

(h, k) = (- \frac{41}{8}, \frac{3}{4}), p = \frac{1}{8}

Solution steps

2 y^{2} - x - 3 y - 4 = 0

Rewrite

2 y^{2} - x - 3 y - 4 = 0

in the standard form

4 \cdot \frac{1}{8} (x - (- \frac{41}{8})) = (y - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{41}{8}, \frac{3}{4}), p = \frac{1}{8}

3000 - p^{2} + 2 q = 0

x^{2} - 24 y = 0

(y + 6)^{2} = \frac{1}{2} (x - 2)

\frac{x ^{2}}{4} = 4 + z

x^{2} + 8 x - 8 y = 16

What is 2y^2-x-3y-4=0 ?
The solution to 2y^2-x-3y-4=0 is Parabola with (h,k)=(-41/8 , 3/4),p= 1/8