What is -16x^2-8y-6=-4x^2 ?

The solution to -16x^2-8y-6=-4x^2 is Parabola with (h,k)=(0,-3/4),p=-1/6

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-16x^2-8y-6=-4x^2

- 16 x^{2} - 8 y - 6 = - 4 x^{2}

(h, k) = (0, - \frac{3}{4}), p = - \frac{1}{6}

Solution steps

- 16 x^{2} - 8 y - 6 = - 4 x^{2}

Rewrite

- 16 x^{2} - 8 y - 6 = - 4 x^{2}

in the standard form:

4 (- \frac{1}{6}) (y - (- \frac{3}{4})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{3}{4}), p = - \frac{1}{6}

2 f (x) - 3 f (x) = x^{2}

f (x) (x)^{- 1} = x + 3

x^{2} + 2 z - 15 = 0

2 x^{2} + 92 = - 4 r (x)

25 y^{2} - x = 0

What is -16x^2-8y-6=-4x^2 ?
The solution to -16x^2-8y-6=-4x^2 is Parabola with (h,k)=(0,-3/4),p=-1/6