What is 16x^2-73z+36=0 ?

The solution to 16x^2-73z+36=0 is Parabola with (h,k)=(0, 36/73),p= 73/64

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16x^2-73z+36=0

16 x^{2} - 73 z + 36 = 0

(h, k) = (0, \frac{36}{73}), p = \frac{73}{64}

Solution steps

16 x^{2} - 73 z + 36 = 0

Rewrite

16 x^{2} - 73 z + 36 = 0

in the standard form:

4 \cdot \frac{73}{64} (z - \frac{36}{73}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{36}{73}), p = \frac{73}{64}

y \geq - 2 x^{2} + 16 x - 29

2 x^{2} + 4 y + 5 = 0

y^{2} = \frac{3}{16} x

(x - 2)^{2} = 12 y

D (h 3 + n) = tt

What is 16x^2-73z+36=0 ?
The solution to 16x^2-73z+36=0 is Parabola with (h,k)=(0, 36/73),p= 73/64