What is y^1=3x^2+5x-2 ?

The solution to y^1=3x^2+5x-2 is Parabola with (h,k)=(-5/6 ,-49/12),p= 1/12

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y^1=3x^2+5x-2

y^{1} = 3 x^{2} + 5 x - 2

(h, k) = (- \frac{5}{6}, - \frac{49}{12}), p = \frac{1}{12}

Solution steps

y^{1} = 3 x^{2} + 5 x - 2

Rewrite

y^{1} = 3 x^{2} + 5 x - 2

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{49}{12})) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, - \frac{49}{12}), p = \frac{1}{12}

3 x^{2} + 5 y = 7 - 2 x

y^{2} - 16 x - 17 = 0

(x - 2) 2 + y^{2} = 16

17 - x + v 169 - x^{2} > 0

y = - \frac{5}{y} x - 1

What is y^1=3x^2+5x-2 ?
The solution to y^1=3x^2+5x-2 is Parabola with (h,k)=(-5/6 ,-49/12),p= 1/12