What is the center 9x^2+16y^2=144 ?

The center 9x^2+16y^2=144 is (0,0)

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center 9x^2+16y^2=144

center

9 x^{2} + 16 y^{2} = 144

(0, 0)

Solution steps

9 x^{2} + 16 y^{2} = 144

Rewrite

9 x^{2} + 16 y^{2} = 144

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

And the center is:

(0, 0)

y^{2} = - 25 x

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{4} = 1

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

y^{2} = - x