What is x^2-40x+16y+160=0 ?

The solution to x^2-40x+16y+160=0 is Parabola with (h,k)=(20,15),p=-4

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x^2-40x+16y+160=0

x^{2} - 40 x + 16 y + 160 = 0

(h, k) = (20, 15), p = - 4

Solution steps

x^{2} - 40 x + 16 y + 160 = 0

Rewrite

x^{2} - 40 x + 16 y + 160 = 0

in the standard form

4 (- 4) (y - 15) = (x - 20)^{2}

Therefore parabola properties are:

(h, k) = (20, 15), p = - 4

x^{2} + (y - 1) = 4

x = y^{2} - 4 y + 17

r^{2} - 7 t + 6 = 0

x = 3 y^{2} - 1

2 (y + 5) = (x + 1)^{2}

What is x^2-40x+16y+160=0 ?
The solution to x^2-40x+16y+160=0 is Parabola with (h,k)=(20,15),p=-4