What is 4x^2+3x=y+2x^2-8 ?

The solution to 4x^2+3x=y+2x^2-8 is Parabola with (h,k)=(-3/4 , 55/8),p= 1/8

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4x^2+3x=y+2x^2-8

4 x^{2} + 3 x = y + 2 x^{2} - 8

(h, k) = (- \frac{3}{4}, \frac{55}{8}), p = \frac{1}{8}

Solution steps

4 x^{2} + 3 x = y + 2 x^{2} - 8

Rewrite

4 x^{2} + 3 x = y + 2 x^{2} - 8

in the standard form

4 \cdot \frac{1}{8} (y - \frac{55}{8}) = (x - (- \frac{3}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{4}, \frac{55}{8}), p = \frac{1}{8}

t (x) = (x - 6)^{2} + 6

- 21 - 3 x^{2} = 4 y + 24 x

x^{2} + 2 x + k (x) > 10

y^{2} - 12 x - 6 y - 15 = 0

9 x^{2} + 9 x + k (x) = 0

What is 4x^2+3x=y+2x^2-8 ?
The solution to 4x^2+3x=y+2x^2-8 is Parabola with (h,k)=(-3/4 , 55/8),p= 1/8