What is ((y+4))/9-((x-3)^2)/(25)=1 ?

The solution to ((y+4))/9-((x-3)^2)/(25)=1 is Parabola with (h,k)=(3,5),p= 25/36

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((y+4))/9-((x-3)^2)/(25)=1

\frac{( y + 4 )}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

(h, k) = (3, 5), p = \frac{25}{36}

Solution steps

\frac{y + 4}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

Rewrite

\frac{y + 4}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

in the standard form:

4 \cdot \frac{25}{36} (y - 5) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 5), p = \frac{25}{36}

x^{2} - 10 x - 78 y = - 25 - 78

x^{2} + 2 y = 60

2 x^{2} + 20 y = 1

y^{2} = 16 (x - 2)

\frac{f ( x )}{100} = - 6.25 x^{2} - 12.5 x + 50

What is ((y+4))/9-((x-3)^2)/(25)=1 ?
The solution to ((y+4))/9-((x-3)^2)/(25)=1 is Parabola with (h,k)=(3,5),p= 25/36