What is 8x^2+23y+15=0 ?

The solution to 8x^2+23y+15=0 is Parabola with (h,k)=(0,-15/23),p=-23/32

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8x^2+23y+15=0

8 x^{2} + 23 y + 15 = 0

(h, k) = (0, - \frac{15}{23}), p = - \frac{23}{32}

Solution steps

8 x^{2} + 23 y + 15 = 0

Rewrite

8 x^{2} + 23 y + 15 = 0

in the standard form:

4 (- \frac{23}{32}) (y - (- \frac{15}{23})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{15}{23}), p = - \frac{23}{32}

(y - \frac{5}{2})^{2} = 4 \cdot 3 \cdot (x - \frac{1}{2})

y^{2} - 5 x - 24 = 0

- x + y^{2} = 1

y^{2} - y = y^{2} + 2 x - 5

x^{2} + 6 x + 20 y - 71 = 0

What is 8x^2+23y+15=0 ?
The solution to 8x^2+23y+15=0 is Parabola with (h,k)=(0,-15/23),p=-23/32