What is (x-2)^2+(y-2)^2=4 ?

The solution to (x-2)^2+(y-2)^2=4 is Circle with (a,b)=(2,2),r=2

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(x-2)^2+(y-2)^2=4

(x - 2)^{2} + (y - 2)^{2} = 4

(a, b) = (2, 2), r = 2

Solution steps

(x - 2)^{2} + (y - 2)^{2} = 4

Rewrite

(x - 2)^{2} + (y - 2)^{2} = 4

in the form of the standard circle equation

(x - 2)^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 2), r = 2

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

y^{2} = - 36 x

x^{2} + \frac{y ^{2}}{16} = 1

x^{2} = - 2 y

What is (x-2)^2+(y-2)^2=4 ?
The solution to (x-2)^2+(y-2)^2=4 is Circle with (a,b)=(2,2),r=2