What is 3a-5(b-a)=(a-b)*(a+b)-a(a-1) ?

The solution to 3a-5(b-a)=(a-b)*(a+b)-a(a-1) is Parabola with (h,k)=(25/28 , 5/2),p=-7/4

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3a-5(b-a)=(a-b)*(a+b)-a(a-1)

3 a - 5 (b - a) = (a - b) \cdot (a + b) - a (a - 1)

(h, k) = (\frac{25}{28}, \frac{5}{2}), p = - \frac{7}{4}

Solution steps

3 a - 5 (b - a) = (a - b) (a + b) - a (a - 1)

Rewrite

3 a - 5 (b - a) - (a - b) (a + b) + a (a - 1) = 0

in the standard form

4 (- \frac{7}{4}) (a - \frac{25}{28}) = (b - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{25}{28}, \frac{5}{2}), p = - \frac{7}{4}

0 = x^{2} + 14 x - 4 y + 48

8 x^{2} + 3 y - 12 x + 6 y + 18 = 0

x^{2} + 6 x + 4 y + 8 = 0

4 x^{2} = 128 y

(y - 4)^{2} = 32 (x - 6)

What is 3a-5(b-a)=(a-b)*(a+b)-a(a-1) ?
The solution to 3a-5(b-a)=(a-b)*(a+b)-a(a-1) is Parabola with (h,k)=(25/28 , 5/2),p=-7/4