What is 5-((4y))/3 =((x^2))/9 ?

The solution to 5-((4y))/3 =((x^2))/9 is Parabola with (h,k)=(0, 15/4),p=-3

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5-((4y))/3 =((x^2))/9

5 - \frac{( 4 y )}{3} = \frac{( x ^{2} )}{9}

(h, k) = (0, \frac{15}{4}), p = - 3

Solution steps

5 - \frac{4 y}{3} = \frac{x ^{2}}{9}

Rewrite

5 - \frac{4 y}{3} = \frac{x ^{2}}{9}

in the standard form:

4 (- 3) (y - \frac{15}{4}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{15}{4}), p = - 3

y^{2} = - 4 (x + 2)

4 y^{2} - 12 x - 16 = 0

- f (x) = 2 x^{2} - x + 3

x^{2} - x - y = 20

f (x) - 4 x^{2} + 12 x + 27 = 35

What is 5-((4y))/3 =((x^2))/9 ?
The solution to 5-((4y))/3 =((x^2))/9 is Parabola with (h,k)=(0, 15/4),p=-3