What is x=40y-800y^2 ?

The solution to x=40y-800y^2 is Parabola with (h,k)=(1/2 , 1/40),p=-1/3200

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x=40y-800y^2

x = 40 y - 800 y^{2}

(h, k) = (\frac{1}{2}, \frac{1}{40}), p = - \frac{1}{3200}

Solution steps

x = 40 y - 800 y^{2}

Rewrite

x = 40 y - 800 y^{2}

in the standard form

4 (- \frac{1}{3200}) (x - \frac{1}{2}) = (y - \frac{1}{40})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{1}{40}), p = - \frac{1}{3200}

x^{2} - 2 y + 10 = 0

2 x^{2} + 5 x - k (x) = 0

x^{2} + (y - 6) 2 = 4

\frac{2 x ^{2} - 28 x}{- k ( x ) - 78} = 1

y = - \frac{1}{12} x^{2} - \frac{4}{3} x - \frac{5}{2}

What is x=40y-800y^2 ?
The solution to x=40y-800y^2 is Parabola with (h,k)=(1/2 , 1/40),p=-1/3200