What is the eccentricity (x^2)/5+(y^2)/9 =1 ?

The eccentricity (x^2)/5+(y^2)/9 =1 is 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/5+(y^2)/9 =1

eccentricity

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1

\frac{2}{3}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{5} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 5

= \frac{3 ^{2} - ( 5 ) ^{2}}{3}

\frac{3 ^{2} - ( 5 ) ^{2}}{3} = \frac{2}{3}

= \frac{2}{3}

3 x^{2} + 2 y^{2} = 6

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

y^{2} + 20 x + 8 y + 56 = 0

x^{2} + y^{2} \leq 16

f (x) = x^{2} + 4 x

What is the eccentricity (x^2)/5+(y^2)/9 =1 ?
The eccentricity (x^2)/5+(y^2)/9 =1 is 2/3