What is -1/4 (x-8)=(y+5)^2 ?

The solution to -1/4 (x-8)=(y+5)^2 is Parabola with (h,k)=(8,-5),p=-1/16

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-1/4 (x-8)=(y+5)^2

- \frac{1}{4} (x - 8) = (y + 5)^{2}

(h, k) = (8, - 5), p = - \frac{1}{16}

Solution steps

- \frac{1}{4} (x - 8) = (y + 5)^{2}

Rewrite

- \frac{1}{4} (x - 8) = (y + 5)^{2}

in the standard form:

4 (- \frac{1}{16}) (x - 8) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (8, - 5), p = - \frac{1}{16}

x^{2} = - 8 (y + 1)

x^{2} - 8 x + y + 8 y + 31 = 0

x 4 x + 3 y = 852

y + 16 = - 2 x^{2} - 12 x

(X - 4)^{2} = 8 (Y + 6)

What is -1/4 (x-8)=(y+5)^2 ?
The solution to -1/4 (x-8)=(y+5)^2 is Parabola with (h,k)=(8,-5),p=-1/16