What is yy-(-4)=0.4(x-(-2)) ?

The solution to yy-(-4)=0.4(x-(-2)) is Parabola with (h,k)=(8,0),p=0.1

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yy-(-4)=0.4(x-(-2))

yy - (- 4) = 0.4 (x - (- 2))

(h, k) = (8, 0), p = 0.1

Solution steps

yy - (- 4) = 0.4 (x - (- 2))

Rewrite

yy - (- 4) = 0.4 (x - (- 2))

in the standard form:

4 \cdot 0.1 (x - 8) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (8, 0), p = 0.1

x^{2} + 2 m (x) + 10 = 0

5 a + 5 \frac{b}{a} = - 5

(x - 2)^{2} = 12 (y + 1)

x = \frac{y - 2}{3 x} \cdot 1

x^{2} - 6 x - 7 y + 16 = 0

What is yy-(-4)=0.4(x-(-2)) ?
The solution to yy-(-4)=0.4(x-(-2)) is Parabola with (h,k)=(8,0),p=0.1