What is ((x-6)/9)^2-((y-4)/5)=1 ?

The solution to ((x-6)/9)^2-((y-4)/5)=1 is Parabola with (h,k)=(6,-1),p= 81/20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-6)/9)^2-((y-4)/5)=1

(\frac{x - 6}{9})^{2} - (\frac{y - 4}{5}) = 1

(h, k) = (6, - 1), p = \frac{81}{20}

Solution steps

(\frac{x - 6}{9})^{2} - \frac{y - 4}{5} = 1

Rewrite

(\frac{x - 6}{9})^{2} - \frac{y - 4}{5} = 1

in the standard form:

4 \cdot \frac{81}{20} (y - (- 1)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 1), p = \frac{81}{20}

5 x^{2} - 2 y + 6 = 0

y \geq - (x - 4)^{2} + 1

x^{2} - 6 x - 16 y + 25 = 0

2 x^{2} + 5 + 2 = - 3 (2 y + 1)

x^{2} + 2 x + 12 y = - 37

What is ((x-6)/9)^2-((y-4)/5)=1 ?
The solution to ((x-6)/9)^2-((y-4)/5)=1 is Parabola with (h,k)=(6,-1),p= 81/20